Suppose R0 = 0x20008000. What Address Is Register R7 Loaded From In The Following Instructions?

ECE 266 – Introduction to Embedded Systems

Fall 2021

Homework #six

Due: Tuesday, Oct. 19, 11:59pm

Notes:

Complete the assignment electronically and submit a PDF file on BlackBoard.

The submission will exist graded by evaluating your effort level, not correctness. You are

expected to testify your best effort, and you may get the credit even if your answers are

not all correct. Specially, for each exercise, yous should ane) show that you accept a correct

understanding of the problem; ii) utilise a reasonable approach to solving the problem; and

iii) if required, testify a complete procedure of solving in add-on to the answer.

It is suggested that you lot complete this week'due south readings earlier you first on the homework.

The number in brackets for each exercise is an indication of the time (in minutes) needed

to consummate the exercise.

If you discuss this homework assignment with any of your classmates, merits so and land

the proper noun(s) of give-and-take participant(s). The discussion should exist almost the noesis

and skills related to the questions, not the solutions. Solution sharing is strictly

prohibited.

Tardily homework is NOT accepted. You may request an extension or exemption for a valid

alibi (emergency, travel, etc.). Send the request by email to the instructor.

Discussed with (if any): __________________

Readings: Textbook, Chapter five, "Load and Store"

one. [10] Textbook Chapter 5, Exercise 5 revised. Given the following retention content:

Memory

address

Data

0x2000800two 0xAone

0xii0008001 010B2

010two000eight000 0xC3

0x20007FFF 010Div

01020007FFE 010Ev

What is the value in register r1 afterward the CPU executes the following instructions if r0 =

0x20008000? Presume the system is little endian (in this course, presume footling endian unless stated

otherwise). The sub-questions are independent.

i) LDRSB r1, [r0]

Loads a byte from the accost #r0 (= 0x20008000), and sign-extends the remaining three higher

bytes in r1.

Now, the byte at 0x20008000 is

Source: https://www.studocu.com/en-us/document/university-of-illinois-at-chicago/intro-to-embedded-systems/homework-6-this-is-a-brief-help-in-hw-6-as-a-study-guide/18671939

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